@Anonymous:
If on Linux the suggested code does not work because '.' and '..' will allways be returned, it may be possible to subtract 2 from the amount of files found.
>>echo (count(glob("$dir/*") - 2) === 0) ? 'Empty' : 'Not
In that way, I think, you have solved the problem of two extra files that are counted.
is_dir
(PHP 4, PHP 5)
is_dir — Tells whether the filename is a directory
Description
bool is_dir
( string $filename
)
Tells whether the given filename is a directory.
Parameters
- filename
-
Path to the file. If filename is a relative filename, it will be checked relative to the current working directory.
Return Values
Returns TRUE if the filename exists and is a directory, FALSE otherwise.
Examples
Example #1 is_dir() example
<?php
var_dump(is_dir('a_file.txt'));
var_dump(is_dir('bogus_dir/abc'));
var_dump(is_dir('..')); //one dir up
?>
The above example will output:
bool(false) bool(false) bool(true)
Notes
Note: The results of this function are cached. See clearstatcache() for more details.
Tip
As of PHP 5.0.0, this function can also be used with some URL wrappers. Refer to List of Supported Protocols/Wrappers for a listing of which wrappers support stat() family of functionality.
is_dir
nielius at gmail dot com
20-Jun-2008 10:21
20-Jun-2008 10:21
Davy Defaud
20-May-2008 11:28
20-May-2008 11:28
Well, "John Doe's function" doesn't return the good value when $file != '.' && $file != '..' it must return false and not true !
Moreover, as the latest contributor told us, the directory have to be closed before returning.
This one is far safer ;-) :
<?php
function is_empty_dir($dir)
{
if ($dh = @opendir($dir))
{
while ($file = readdir($dh))
{
if ($file != '.' && $file != '..') {
closedir($dh);
return false;
}
}
closedir($dh);
return true;
}
else return false; // whatever the reason is : no such dir, not a dir, not readable
}
?>
Anonymous
24-Apr-2008 09:31
24-Apr-2008 09:31
On the previous example you may want to closedir() before returning, I tried the function and ran into some locking issues on windows when trying to delete the directory after I ran this function.
John Doe
23-Apr-2008 02:06
23-Apr-2008 02:06
I altered the function below a bit. This implementation is simpler, faster and safer:
<?php
function is_empty_folder($folder) {
if (! is_dir($folder))
return false; // not a dir
$files = opendir($folder);
while ($file = readdir($files)) {
if ($file != '.' && $file != '..')
return true; // not empty
}
}
?>
vlasec at gmailcom
23-Mar-2008 12:34
23-Mar-2008 12:34
zombix:
I don't know much about implementation, however I think that passing through all the files is useless. This code returns false also in case that it's not even a folder plus it stops in three steps at most.
<?php
function is_empty_folder($folder){
$c=0;
if(is_dir($folder) ){
$files = opendir($folder);
while ($file=readdir($files)){
$c++;
if ($c>2)
return false; // dir contains something
}
return true; // empty dir
}
else return false; // not a dir
}
?>
zombix at metrohive dot net
17-Mar-2008 07:14
17-Mar-2008 07:14
to check if folder is empty
function is_empty_folder($folder){
$c=0;
if(is_dir($folder) ){
$files = opendir($folder);
while ($file=readdir($files)){$c++;}
if ($c>2){
return false;
}else{
return true;
}
}
}
Anonymous
18-Dec-2007 07:51
18-Dec-2007 07:51
One note regarding checking for empty directories :
>>echo (count(glob("$dir/*")) === 0) ? 'Empty' : 'Not empty';
This does not work correctly on Linux.
The '.' and '..' will always be returned even if no files are present in the directory.
sgoldbroch at DONTSPAMMEcmcplacce dot com
05-Dec-2007 10:25
05-Dec-2007 10:25
Took a while to figure this out, but - DONT USE THIS IN A LOOP WITH READDIR()! readdir() only gives the file/dir name and not the full path which is_dir apparently needs to be able to accurately evaluate the argument.
e dot loiseau at meteo-ondemand dot com
29-Jul-2007 07:42
29-Jul-2007 07:42
I had the same problem as others with not using the complete path to a folder when usin is_dir.
It's really important to use complete path.
$folder = "../pictures";
$dossier = opendir($folder);
while ($Fichier = readdir($dossier)) {
if ($Fichier != "." && $Fichier != ".." && $Fichier != "Thumbs.db") {
// if(is_dir($Fichier)) { // Do not always works
if(is_dir($folder."/".$Fichier)) { // Works always
echo "$Fichier";
} // fin if is file
} // fin if restriction des fichiers à ne pas afficher
} // fin while
closedir($dossier);
Edouard
danr at cvisual dot com dot com
18-Jul-2007 10:54
18-Jul-2007 10:54
Running PHP 5.2.0 on Apache Windows, I had a problem (likely the same one as described by others) where is_dir returned a False for directories with certain permissions even though they were accessible.
Strangely, I was able to overcome the problem with a more complete path. For example, this only displays "Works" on subdirectories with particular permissions (in this directory about 1 out of 3):
$d = opendir("./albums/mydir");
while(false !== ($f = readdir($d))) {
echo "<hr />";
if(is_dir($f)) {
echo "<b>Works:" . $f . "</b>";
}
}
However, this works properly for all directories:
$d = opendir("./albums/mydir");
while(false !== ($f = readdir($d))) {
echo "<hr />";
$dName = "./albums/mydir/" . $f;
if(is_dir($dName)) {
echo "<b>Works:" . $dName . "</b>";
}
}
I don't understand the hit-and-miss of the first code, but maybe the second code can help others having this problem.
legolas558 d0t users dot sf dot net
20-May-2007 02:33
20-May-2007 02:33
I had troubles at checking for the existance of a directory under the windows temporary path (usually c:\windows\temp\). I am using PHP 5.2.0
See also the bug tracker item: http://bugs.php.net/bug.php?id=39198
Here below the replacement function which works under the Windows temporary directory. It is a bad hack, since it creates and then removes the directory to verify its existance! But I could not find an alternative solution, that bug should be fixed.
<?php
function temp_is_dir($dir) {
// check directory existance under temp folder (tested on Windows)
// see bug #31918 http://bugs.php.net/bug.php?id=39198
// by legolas558
if (!@mkdir($dir))
return true;
rmdir($dir);
return false;
}
?>
lordalderaan at gmail dot com
11-May-2007 02:26
11-May-2007 02:26
As was said earlier by locataweb at hotmail dot com is_dir returns false on windows shares even if they exist and are accessible.
I found that is_readable provides about the same functionality and does return true. It might provide a sufficient replacement in most cases.
gecko4 at gmail dot com
25-Feb-2007 05:03
25-Feb-2007 05:03
Here is another way to test if a directory is empty, which I think is much simpler than those posted below:
<?php
$dir = 'directory';
echo (count(glob("$dir/*")) === 0) ? 'Empty' : 'Not empty';
?>
18-Jan-2007 01:07
Be aware that is_dir() and is_file() will not work on very large (for me >2gb) files (also see http://de3.php.net/manual/en/function.is-file.php#56334).
You might try this approach - it works for me:
<?php
function isDir($dir) {
$cwd = getcwd();
$returnValue = false;
if (@chdir($dir)) {
chdir($cwd);
$returnValue = true;
}
return $returnValue;
}
?>
Please keep in mind that isDir() will fail on directories which cannot be chdired due to permission settings for example.
Eric
24-Oct-2006 09:53
24-Oct-2006 09:53
Ah ha! Maybe this is a bug, or limitation to be more precise, of php. See http://bugs.php.net/bug.php?id=27792
A workaround is posted on the page (above) and seems to work for me:
function is_dir_LFS($path){
return (('d'==substr(exec("ls -dl '$path'"),0,1))?(true):(false));
}
PS: I'm using PHP 4.3.10-16, posts report this problem up to 5.0
Eric Peterson
24-Oct-2006 01:48
24-Oct-2006 01:48
I'm not sure what is going on here... I have a function to return a listing of (sub)directories within a directory. Works great until I ran into the directory given in the warning below... 87 characters seems too short to be running into a file/directory name length issue?
This is what I'm getting (though broken into a couple lines so this forum will accept it):
Warning: is_dir(): Stat failed for
/home/office/public_html/Library/1_NNHP-produced/4_Maps
/Peterson2003/BRTEreport_DVD.zip
(errno=75 - Value too large for defined data type) in /home/office/public_html/index.php on line 104
Here is line 104:
if (is_dir($dir . "/" . $listing)) {
alan dot rezende at light dot com dot br
29-Sep-2006 02:42
29-Sep-2006 02:42
The function is_dir will always return false if the handle acquired with opendir is not from the current working directory (getcwd); exception applies to "." and "..". Thus, if you need a consistent dir listing from any directory other than the current one, you must change dir first. Example follows:
<?php
chdir( '..' );
$rep=opendir('.');
while (false != ($file = readdir($rep))){
if (is_dir($file)){
print("<a href='$file/' class='text1'>$file</a>");
}
}
?>
The above code will list all directories (with links) for the ".." directory, relative to the current working dir.
THE WRONG WAY TO DO IT FOLLOWS:
<?php
$rep=opendir('..');
while (false != ($file = readdir($rep))){
//print "$file is here (may be a dir or not)<br>";
if (is_dir($file)){
print "<a href='$file/' class='text1'>$file</a><br>";
}
}
?>
This code will turn into an empty list. If you want to make sure, uncomment the commented line...
Regards...
locataweb at hotmail dot com
06-Aug-2006 11:59
06-Aug-2006 11:59
NOTE on Windows Shares (based on tests using PHP 5.1.1):
After many hours of head scratching and wondering why a script worked sometimes but not others, I discovered this revelation.
Be aware that base Windows shares are not recognised as dirs, so the following test will return false even if \\COMPUTER_NAME\SHARENAME exists.
<?php
if (is_dir('\\\\COMPUTER_NAME\\SHARENAME')) {
echo "TRUE\n";
}
else {
echo "FALSE\n";
}
//will return FALSE;
// However testing a subdir of the same base share
// using test below will return TRUE,
// despite the fact the parent base Windows share
// returns false when tested by is_dir()
is_dir('\\\\COMPUTER_NAME\\SHARENAME\\SUBDIR') {
echo "TRUE\n";
} else {
echo "FALSE\n";
}
//will return TRUE.
?>
As a work round I replaced is_dir with is_readable() instead, which identifies if the share is readable and so must exist, but this is clearly dependent on whether the share is readable.
I hope this helps someone. If there is a better work round or other purpose built solution to this problem with base windows shares, please post them so I'll know the next time.
derek at nospam dot pmachine dot com
15-Jul-2006 12:10
15-Jul-2006 12:10
regarding dmertens-php-note at zyprexia dot com's statement on 24-Sep-2005 09:53
Actually, is_dir is not affected by UID checks in safe_mode. is_dir will even return true if you lack sufficient privileges to read said directory.
dmertens-php-note at zyprexia dot com
24-Sep-2005 04:53
24-Sep-2005 04:53
Remember that the owner of the directory has to be the same of the script user, otherwise this function will always return false when PHP is running in safe_mode..
fanfatal at fanfatal dot pl
02-Jul-2005 05:04
02-Jul-2005 05:04
Hi
I wrote an usefull function to check is directory exists in directory's tree ;)
<?php
/*
* Function to check recursively if dirname is exists in directory's tree
*
* @param string $dir_name
* @param string [$path]
* @return bool
* @author FanFataL
*/
function dir_exists($dir_name = false, $path = './') {
if(!$dir_name) return false;
if(is_dir($path.$dir_name)) return true;
$tree = glob($path.'*', GLOB_ONLYDIR);
if($tree && count($tree)>0) {
foreach($tree as $dir)
if(dir_exists($dir_name, $dir.'/'))
return true;
}
return false;
}
?>
Greatings ;)
...
06-Jun-2005 07:30
With error reporting set to all, and you attempt to do:
echo var_dump(is_dir('bogus_dir/abc'));
as output you will get:
Warning: stat failed for bogus_dir/abc (errno=2 - No such file or directory) in test.php on line 12
bool(false)
If you want to use this with an error reporting level set to all, you will need to use @ to supress the generated error
akashif at freezone dot co dot uk
03-Jun-2005 12:50
03-Jun-2005 12:50
just a simple script to for those who dont have the IIS or Apache Dirlisting available , this will make onr for you
<?php
$DirPath=$_GET['DirPath'];
if($DirPath=="")
{
$DirPath='./';
}
if (($handle=opendir($DirPath)))
{
while ($node = readdir($handle))
{
$nodebase = basename($node);
if ($nodebase!="." && $nodebase!="..")
{
if(is_dir($DirPath.$node))
{
$nPath=$DirPath.$node."/";
echo "-> -> -> <a href='dir.php?DirPath=$nPath'>$node</a><br>";
}
else
{
echo "<a href='$node'>$node</a><br>";
}
}
}
}
?>
renich at woralelandia dot com
21-Apr-2005 07:45
21-Apr-2005 07:45
Here goes a PHP5.0 link-to-directory listing function and examples
<?php
//List directories only
function list_dirs($path, $target)
{
$list = scandir($path);
foreach ($list as $number => $filename)
{
if ( $filename !== '.' && $filename !== '..' && is_dir("$path/$filename") )
{
// Asign more readable and logic variables
$dir = $filename;
$url = apache_request_headers();
if ($target == '')
{
// Print Dirs with link
print ("<a href=\"http://$url[Host]/$path/$dir\">$dir</a> <br>\n");
}
else
{
// Print Dirs with link
print ("<a href=\"http://$url[Host]$dir\" target=\"$target\">$dir</a> <br>\n");
}
}
}
}
?>
1.- List current directory's directories with no target property.
<?php
list_dirs('.','')
?>
2.- List "libraries" in "pma2" located at my dir with a "_blank" target set
<?php
list_dirs('pma2/libraries','_blank');
?>
or
<?php
list_dirs('/var/www/html/pma2/libraries','_blank');
?>
3.- List all the directories located at the "/Home" dir with "_me" as target.
<?php
list_dirs('/home', ''_me');
?>
I hope you all like it!
Note:
Obviously, the links will now work if the're not in the apache dir... ("htdocs", "html", "www", whatever)
dusted19 at hotmail dot com
19-Mar-2005 10:38
19-Mar-2005 10:38
While working on a php project (my first one =( ). I ran into a bug using is_dir() on my winxp w/ servicepack 2 system. I'm using php 4.3.10.. the problem is whenever i pass is_dir() a pathname that is longer then 256 characters long it will ALWAYS return true.
CODE:
<?php
// Path to multimedia files
$mpath = "E:\\armoury\\";
ls($mpath);
//echo "MP3 Listing:<br/><br/>";
function ls ($curpath) {
$dir = dir($curpath);
echo("<b>$curpath</b>");
echo "<blockquote>";
while ($file = $dir->read()) {
echo(" <b>");
echo(strlen($curpath.$file));
echo("</b> ");
if($file != "." && $file != "..") {
if (is_dir($curpath.$file)) {
ls($curpath.$file."\\");
} else {
echo(" $file<br>");
}
}
// }
}
$dir->close();
echo "</blockquote>";
return;
}
?>
This is the output.. the number preceding the file/directory is the number of characters in it's full path name. You can see where it trips up at:
257 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3
The pathname is greater then 256 characters.
229 A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 07 - Bonita Applebum.mp3
227 A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 08 - Can I Kick It.mp3
233 A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 09 - Youthful Expression.mp3
257 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3\
259 260 267 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3\index.php\
269 270 277 E:\armoury\[ hiphop - dub - reggae - soul ]\A Tribe Called Quest - 1990 - People's Instinctive Travels And The Paths Of Rhythm\A Tribe Called Quest - People's Instinctive Travels And The Paths Of Rhythm - 10 - Rhythm (Devoted To The Art Of Moving Butts).mp3\index.php\index.php\
Try it yourself on a large directory structure.
flobee
14-Mar-2005 02:13
14-Mar-2005 02:13
note: like the main example already shows. tooks me houres to understand und using chdir() to get a full dir scann (especilly on windows and "mounted" network drives)
never forget the tailing slash to find out if you have a directory or not.
<?php
function parse_dir($dir) {
if ($dh = @opendir($dir)) {
while(($file = readdir($dh)) !== false) {
if( !preg_match('/^\./s', $file) ) {
if(is_dir($dir.$file)) {
$newdir = $dir.$file.'/'; // <- tailing slash
chdir($newdir);
echo "IS DIR: $newdir\n";
echo parse_dir($newdir);
} else {
echo $dir.$file."\n";
}
}
}
chdir('..');
}
}
parse_dir('z:/myfolder/mysubfolder/');
?>
puremango dot co dot uk at gmail dot com
08-Feb-2005 07:55
08-Feb-2005 07:55
this function bypasses open_basedir restrictions.
<?
function my_is_dir($dir)
{
// bypasses open_basedir restrictions of is_dir and fileperms
$tmp_cmd = `ls -dl $dir`;
$dir_flag = $tmp_cmd[0];
if($dir_flag!="d")
{
// not d; use next char (first char might be 's' and is still directory)
$dir_flag = $tmp_cmd[1];
}
return ($dir_flag=="d");
}
?>
example:
<?
....
echo is_dir("/somewhere/i/dont/have/access/to");
?>
output:
Warning: open_basedir restriction in effect
<?
....
echo my_is_dir("/somewhere/i/dont/have/access/to");
?>
output:
true (or false, depending whether it is or not...)
---
visit puremango.co.uk for other such wonders
03-Feb-2005 12:12
Unfortunately, the function posted by p dot marzec at bold-sg dot pl does not work.
The corrected version is:
// returns true if folder is empty or not existing
// false if folde is full
function is_empty_folder($dir) {
if (is_dir($dir)) {
$dl=opendir($dir);
if ($dl) {
while($name = readdir($dl)) {
if (!is_dir("$dir/$name")) { //<--- corrected here
return false;
break;
}
}
closedir($dl);
}
return true;
} else return true;
}
tibard at gmail dot com
01-Feb-2005 08:32
01-Feb-2005 08:32
use this function to get all files inside a directory (including subdirectories)
<?php
function scan_Dir($dir) {
$arrfiles = array();
if (is_dir($dir)) {
if ($handle = opendir($dir)) {
chdir($dir);
while (false !== ($file = readdir($handle))) {
if ($file != "." && $file != "..") {
if (is_dir($file)) {
$arr = scan_Dir($file);
foreach ($arr as $value) {
$arrfiles[] = $dir."/".$value;
}
} else {
$arrfiles[] = $dir."/".$file;
}
}
}
chdir("../");
}
closedir($handle);
}
return $arrfiles;
}
?>
rchavezc at ameritech dot net
12-Dec-2004 04:19
12-Dec-2004 04:19
This is the function that I use to test for an empty directory:
<?php
function is_emtpy_dir($dirname){
// Returns true if $dirname is a directory and it is empty
$result=false; // Assume it is not a directory
if(is_dir($dirname) ){
$result=true; // It is a directory
$handle = opendir($dirname);
while( ( $name = readdir($handle)) !== false){
if ($name!= "." && $name !=".."){
$result=false; // directory not empty
break; // no need to test more
}
}
closedir($handle);
}
return $result;
}
?>
bhuskins at nospam dot christian-horizons dot org
12-Aug-2004 09:51
12-Aug-2004 09:51
'Is_empty_folder' posted by andreas at rueping dot net is a nice function. It did give me some grief, though. I don't beleive that it actually closes the directory when it's done (closedir in the wrong spot). I changed it slightly to be the following:
// returns true if folder is empty or not existing
// false if folde is full
<?
function is_emtpy_folder($folder){
if(is_dir($folder) ){
$handle = opendir($folder);
while( (gettype( $name = readdir($handle)) != "boolean")){
$name_array[] = $name;
}
foreach($name_array as $temp)
$folder_content .= $temp;
closedir($handle);//<--------moved this
if($folder_content == "...") {
return true;
} else {
return false;
}
}
else
return true; // folder doesnt exist
}
?>
sly at noiretblanc dot org
28-May-2004 06:10
28-May-2004 06:10
This is the "is_dir" function I use to solve the problems :
function Another_is_dir ($file)
{
if ((fileperms("$file") & 0x4000) == 0x4000)
return TRUE;
else
return FALSE;
}
or, more simple :
function Another_is_dir ($file)
{
return ((fileperms("$file") & 0x4000) == 0x4000);
}
I can't remember where it comes from, but it works fine.
p dot marzec at bold-sg dot pl
14-Mar-2004 03:33
14-Mar-2004 03:33
Simplest version 'is_empty_folder' posted by andreas at rueping dot net
// returns true if folder is empty or not existing
// false if folde is full
function is_empty_folder($dir) {
if (is_dir($dir)) {
$dl=opendir($dir);
if ($dl) {
while($name = readdir($dl)) {
if (!is_dir($name)) {
return false;
break;
}
}
closedir($dl);
}
return true;
} else return true;
}
andreas at rueping dot net
24-Sep-2003 01:29
24-Sep-2003 01:29
function checks if a folder is empty or not. Retruns "true" if it is empty and "false" if it is full with data. Also if the folder doesnt even exist, function returns "true".
--------------------------------------------------
--------------------------------------------------
// returns true if folder is empty or not existing
// false if folde is full
<?
function is_emtpy_folder($folder){
if(is_dir($folder) ){
$handle = opendir($folder);
while( (gettype( $name = readdir($handle)) != "boolean")){
$name_array[] = $name;
}
foreach($name_array as $temp)
$folder_content .= $temp;
if($folder_content == "...")
return true;
else
return false;
closedir($handle);
}
else
return true; // folder doesnt exist
}
?>
