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mysql_drop_db> <mysql_db_name
Last updated: Fri, 16 May 2008

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mysql_db_query

(PHP 4, PHP 5, PECL mysql:1.0)

mysql_db_query — Send a MySQL query

Description

resource mysql_db_query ( string $database , string $query [, resource $link_identifier ] )

mysql_db_query() selects a database, and executes a query on it.

Parameters

database

The name of the database that will be selected.

query

The MySQL query.

link_identifier

The MySQL connection. If the link identifier is not specified, the last link opened by mysql_connect() is assumed. If no such link is found, it will try to create one as if mysql_connect() was called with no arguments. If by chance no connection is found or established, an E_WARNING level error is generated.

Return Values

Returns a positive MySQL result resource to the query result, or FALSE on error. The function also returns TRUE/FALSE for INSERT/UPDATE/DELETE queries to indicate success/failure.

ChangeLog

Version Description
4.0.6 This function is deprecated, do not use this function. Use mysql_select_db() and mysql_query() instead.

Examples

Example #1 mysql_db_query() alternative example

<?php

if (!$link mysql_connect('mysql_host''mysql_user''mysql_password')) {
    echo 
'Could not connect to mysql';
    exit;
}

if (!
mysql_select_db('mysql_dbname'$link)) {
    echo 
'Could not select database';
    exit;
}

$sql    'SELECT foo FROM bar WHERE id = 42';
$result mysql_query($sql$link);

if (!
$result) {
    echo 
"DB Error, could not query the database\n";
    echo 
'MySQL Error: ' mysql_error();
    exit;
}

while (
$row mysql_fetch_assoc($result)) {
    echo 
$row['foo'];
}

mysql_free_result($result);

?>

Notes

Note: Be aware that this function does NOT switch back to the database you were connected before. In other words, you can't use this function to temporarily run a sql query on another database, you would have to manually switch back. Users are strongly encouraged to use the database.table syntax in their sql queries or mysql_select_db() instead of this function.



add a note add a note User Contributed Notes
mysql_db_query
Anonymous
02-May-2008 07:21
<div id="vypis">
  <?php
 
if ($_SESSION['vstup']==1)
  {
 
$sql="SELECT * from mess WHERE cil='all' OR cil='$nick' OR autor='$nick'";
 
$data=mysql_query($sql);  //echo $data;
 
while (($pole=mysql_fetch_array($data))!=FALSE)
    {
     
$cas=$pole['cas'];
     
$autor=$pole['autor'];
     
$text=$pole['text'];
     
$cil=$pole['cil'];
     
$sipka="►";
      echo
"<p><span class='fat'>";
      echo
$cas."&nbsp;";
      echo
$autor;
      if (
$cil!="all") {echo $sipka."&nbsp;".$cil.":&nbsp;";}else{echo ":&nbsp;";}
      echo
"</span>".$text."&nbsp;";
      echo
"</p>";
    }
   }
 
?>
 </div>
 
 <div id="panel">
 <p>
 <?php
 $sql
="SELECT nick from user_list WHERE status='1'";
 
$data=mysql_query($sql);
 while((
$pole=mysql_fetch_array($data))!=FALSE)
 {
  echo
$pole['nick']."<br />";
 }
 
?>
</p>
 <form action="/script/logout.php">
 <input type="submit" value="log me out" id="logout">
 </form>
 </div>
 
 <div id="bottomline">
 <form action="/script/write.php" method="get">
 <?php
 
echo $nick.":&nbsp;";
 
?>
<label for="mess">message: &nbsp; </label> <input type="text" name="text" id="mess">
 <label for="seznam"> send to &nbsp;</label>
 <select name="cil" size="1" id="seznam">
 <option value="all">all users
 <?php
 $sql
="SELECT nick from user_list WHERE status='1'";
 
$data=mysql_query($sql);
  echo
"<p>";
 while ((
$pole=mysql_fetch_array($data))!=FALSE)
 {echo
"<option value='".$pole['nick']."'>".$pole['nick']."<br />";}
  echo
"</p>";
 
$_SESSION['vstup']=1;
 
?>
</select>
 <input type="submit" value="sen the message" id="subac"><br />
 </form>

mysql_drop_db> <mysql_db_name
Last updated: Fri, 16 May 2008
 
 
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